NCERT Notes for Class 9 Math Chapter 13 Surface Areas and Volumes Notes
Class 9 Maths Chapter 13 Surface Areas and Volumes Notes
Chapter Name | Surface Areas and Volumes Notes |
Class | CBSE Class 9 |
Textbook Name | Surface Areas and Volumes Class 9 |
Related Readings |
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Plane figure
The figures which we can draw on a piece of paper or which lie on a plane are called Plane Figures. Example: Circle, Square, Rectangle etc.Solid figures
The 3D shapes which occupy some space are called Solid Figures. Example: Cube, Cuboid, Sphere etc.
Volume
Space occupied by any solid shape is the capacity or volume of that figure. The unit of volume is a cubic unit.
Surface Area
The area of all the faces of the solid shape is the total surface area of that figure. The unit of surface area is a square unit.
Lateral or Curved Surface Area
The surface area of the solid shape after leaving the top and bottom face of the figure is called the lateral surface of the shape. The unit of lateral surface area is a square unit.
Surface Area and Volume of a Cube
Cube is a solid shape having 6 equal square faces.
|
Lateral surface area of a cube |
4l2 |
|
Total surface area of a cube |
6l2 |
|
The volume of a cube |
l3 |
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Diagonal |
√3l, l = edge of the cube |
Example: What is the capacity of a cubical vessel having each side of 8 cm?
Solution
Given side = 8 cm
So, Volume of the cubical vessel = l3
= (8)3 = 256 cm3 .
Surface Area and volume of a Cuboid
Cuboid is a solid shape having 6 rectangular faces at a right angle.
|
Lateral surface area of a cuboid |
2h(l + b) |
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Total surface area of a cuboid |
2(lb + bh + lh) |
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Volume of a cuboid |
lbh |
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Diagonal |
 |
Example: What is the surface area of a cereal box whose length, breadth and height is 20 cm, 8 cm and 30 cm respectively?
Solution
Given,
Length = 20 cm
Breadth = 8 cm
Height = 30 cm
Total surface area of the cereal box = 2(lb + bh + lh)
= 2(20 × 8 + 8 × 30 + 20 × 30)
= 2(160 + 240 + 600)
= 2(1000) = 2000 cm2 .
Surface Area and Volume of a Right Circular Cylinder
If we fold a rectangular sheet with one side as its axis then it forms a cylinder. It is the curved surface of the cylinder. And if this curved surface is covered by two parallel circular bases then it forms a right circular cylinder.
Curved surface area of a Right circular cylinder | 2Ï€rh |
Total surface area of a Right circular cylinder | 2Ï€r2 + 2Ï€rh = 2Ï€r(r + h) |
The volume of a Right circular cylinder | πr2 |
r = radius, h = height |
Surface Area and Volume of a Hollow Right Circular Cylinder
If a right circular cylinder is hollow from inside then it has different curved surface and volume.
|
Curved surface area of a Right circular cylinder |
2Ï€h (R + r) |
|
Total surface area of a Right circular cylinder |
2Ï€h (R + r) + 2Ï€(R2 − r2) |
|
|
R = outer radius, r = inner radius |
Example: Find the Total surface area of a hollow cylinder whose length is 22 cm and the external radius is 7 cm with 1 cm thickness. (Ï€ = 22/7)
Solution
Given, h = 22 cm
R = 7 cm
r = 6 cm (thickness of the wall is 1 cm)
Total surface area of a hollow cylinder = 2Ï€h(R + r) + 2Ï€(R2 – r2 )
= 2(Ï€) (22) (7+6) + 2(Ï€)(72 – 62 )
= 572 π + 26 π = 598 π
= 1878.67 cm2
Surface Area and Volume of a Right Circular Cone
If we revolve a right-angled triangle about one of its sides by taking other as its axis then the solid shape formed is known as a Right Circular Cone.
|
Curved surface area of a Right Circular Cone |
 |
|
Total surface area of a Right Circular Cone |
πr2 + πrl = πr(r + l) |
|
The volume of Right Circular Cone |
(1/3) πr2h |
|
|
r = radius, h = height, l = slant height |
Surface Area and Volume of a Sphere
A sphere is a solid shape which is completely round like a ball. It has the same curved and total surface area.
|
Curved or Lateral surface area of a Sphere |
4Ï€r2 |
|
Total surface area of a Sphere |
4Ï€r2 |
|
Volume of a Sphere |
(4/3) πr3 |
|
|
R = radius |
Surface Area and Volume of a Hemisphere
If we cut the sphere in two parts then is said to be a hemisphere.
|
Curved or Lateral surface area of a Sphere |
2Ï€r2 |
|
Total surface area of a Sphere |
3Ï€r2 |
|
Volume of a Sphere |
(2/3) πr3 |
|
|
r = radius |
Example: If we have a metal piece of cone shape with volume 523.33 cm3 and we mould it in a sphere then what will be the surface area of that sphere?
Solution
Given, volume of cone = 523.33 cm3
Volume of cone = Volume of Sphere
Volume of sphere = 100 π cm3
⇒ 125 = r3
⇒ r = 5
Surface area of a sphere = 4Ï€r2
= 314.28 cm2 .