ICSE Revision Notes for Uses of Ammonium Hydroxide and Sodium Hydroxide Class 10 Chemistry
Chapter Name | Uses of Ammonium Hydroxide & Sodium Hydroxide |
Topics Covered |
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Related Study |
Analytical Chemistry
In the qualitative analysis of compounds, their colour helps in their identification. The table given below shows some examples of colourless and coloured ions.
Colourless |
Coloured |
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Cation |
Symbol |
Cation |
Symbol |
Colour |
|
Ammonium |
NH4+ |
Cupric |
Cu2+ |
Blue |
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Sodium |
Na+ |
Ferrous |
Fe2+ |
Light Green |
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Potassium |
K+ |
Ferric |
Fe3+ |
Yellowish-brown |
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Calcium |
Ca+ |
Nickel |
Ni2+ |
Green |
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Magnesium |
Mg2+ |
Chromium |
Cr3+ |
Green |
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Aluminium |
Al3+ |
Manganese |
Mn2+ |
Pink |
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Lead |
Pb2+ |
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Zinc |
Zn2+ |
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Chemical reactions of the soluble salt solutions with NaOH and NH4OH
Some soluble salts (except sodium and potassium) react with sodium hydroxide and ammonium hydroxide to form insoluble precipitates.
Reactions with sodium hydroxide solution
Aqueous ferrous sulphate (green in colour) reacts with NaOH to form iron (II) hydroxide, which is insoluble in alkali.
FeSO4 + 2NaOH → Na2SO4 + Fe(OH)2
Other such reactions are shown below:
Reactions with ammonium hydroxide
Aqueous ferrous sulphate (green in colour) reacts with NH4OH to form iron (II) hydroxide, which is insoluble in excess of ammonium hydroxide.
FeSO4 + 2NH4OH → (NH4)2SO4 + Fe(OH)2
Other such reactions are shown below:
Amphoteric nature of zinc and aluminium metals, their oxides and hydroxides
Amphoteric nature of zinc and aluminium metals: As zinc and aluminium metals displace hydrogen from the acids as well as alkali, therefore, they are amphoteric in nature.
Zn + H2SO4 (dil.) → ZnSO4 + H2(g)
2Al + 3H2SO4 (dil.) → Al2(SO4)3 + 3H2 (g)
Zn + H2SO4 (dil.) → ZnSO4 + H2O
Al2O3 + 3H2SO4 (dil.) → Al2(SO4)3 + 3H2O
Amphoteric nature of hydroxides of zinc and aluminium metals: As the hydroxides of zinc and aluminium react with acids as well as alkalies to form salt and water as the only products, therefore, they are amphoteric in nature.
PbO + 2HCl → PbCl2 + H2O
PbO + 2NaOH + H2O → Na2[Pb(OH)4]
Pb(OH)2 + 2NaOH → Na2[Pb(OH)4