ICSE Solutions for Selina Concise Chapter 2 Compound Interest (using formula) Class 9 Maths
Exercise 3(A)
1. Find the amount and the compound interest on Rs. 12,000 in 3 years at 5% compounded annually.Answer
Given : P= Rs. 12,000; n = 3 years and r = 5%
= Rs. 13,891.50
C.I. = Rs. 13,891.50 – Rs. 12,000 = Rs. 1,891.50.
Answer
Given : P = Rs. 15,000; n = 2 years; r1 = 8 % and r2 = 10%
= Rs. 17,820.
Answer
Given : P = Rs. 6,000; n = 3 years; r1 = 5%; r2 = 8% and r3 = 10%
= Rs. 7,484.40
∴ C.I. = Rs. 7,484.40 – Rs. 6,000 = Rs. 1,484.40.
Answer
Given: P= Rs. 5,445 ; n = 2 years and r = 10%
= Rs. 4,500
Answer
Given : C.I.= Rs. 768.75; n= 2 years and r = 5%
Answer
Given : C.I. = Rs. 1,655; n = 3 years and r = 10%
Answer
Given : A = Rs. 9,856 ; n = 2 years ; r1 = 10 % and r2 = 12%
8. On a certain sum, the compound interest in 2 years amounts to Rs. 4,240. If the rate of interest for the successive years is 10% and 15% respectively, find the sum.
Answer
⇒ (P + 4240) = P(1.265)
⇒ P = Rs. 16000
The sum is Rs.16,000.
Answer
At 5% per annum the sum of Rs. 6,000 amounts to Rs. 6,615 in 2 years when the interest is compounded annually.
Answer
Let Principal = Rs. y
Then Amount= Rs 1.44y
n= 2 years
On solving, we get r = 20 %
Answer
Given : P = Rs. 4,000, C.I. = Rs. 1,324 and n = 3 years
Now, A = P + I
⇒ A = Rs. (4,000 + 1,324) = Rs. 5,324
Thus, the rate of interest is 10%.
(ii) the amount at the end of the third year.
Answer
Given: P = Rs. 5,000; A = Rs. 6,272 and n = 2 years.
= Rs. 7,024.64
Answer
Given : P = Rs. 7,000; A = Rs. 9,317 and r = 10%.
On comparing, n = 3 years
Answer
Given : P= Rs. 4,000; C.I.= Rs. 630.50 and r = 5%
On comparing, n = 3 years
Answer
Let share of A = Rs. y
share of B = Rs (28,730 – y)
rate of interest= 10%
According to question,
Amount of A in 3 years= Amount of B in 5 years
Therefore, share of A = Rs. 15,730
Share of B = Rs. 28,730 – Rs.15,730 = Rs. 13,000
Answer
(i) Let share of John = Rs y
share of Smith = Rs (44,200 – y)
rate of interest= 10%
According to question,
Amount of John in 4 years = Amount of Smith in 2 years
= Rs. 29,282
- the sum.
- the amount due to the end of 3 years and at the same rate of interest compounded annually.
- the compound interest earned in 3 years.
Answer
(i) I = Rs. 6,000, T = 2 years and R = 10%
= Rs. 39,930
(iii) C.I. earned in 3 years = A – P = Rs. (39,930 – 30,000) = Rs. 930.
Answer
Given: P = Rs. 8,000, R = 5%, T = 2 years
For simple interest,
C.I. = A - P
= Rs. (8,820 – 8,000)
= Rs. 820
Now, C.I. – S.I. = Rs. (820 – 800) = Rs. 20.
Thus, the difference between the compound interest and the simple interest is Rs. 20.
Exercise 3(B)
Answer
Let principal (P) = x
R = 8%
T = 2 years
X = Rs. 8500
Thus, principal sum = Rs. 8500
Answer
(for 2 years) A = Rs. 19360
T = 2 years
Let P = X
X = Rs. 16,000
Thus, sum = Rs. 16000
Answer
Let principal = X, A = 3X, T = 8 years, R = ?
Case I,
T = 24
Time = 24 years.
Answer
P = Rs. 9430
R = 5%
T = 10 years
Thus, principal from = Rs. 46,000
Answer
Let principal = Rs. 100, R = 5% T = 2 years
= Rs. 615
Answer
SI = Rs. 450
R = 4%
T = 2 years
P = ?
CI = A - P = 6084 - 5625 = Rs. 459
Answer
Let principal (P), R = 4%, T = 4 years
P = Rs. 96000
Thus, Principal = Rs. 96000
Answer
CI = Rs. 246, R = 5%, T = 2 years
CI = A – P
9. A certain sum of money amounts to Rs. 23,400 in 3 years at 10% per annum simple interest. Find the amount of the same sum in 2 years and at 10% p.a. compound interest.
Answer
Let the sum (principle) = X
Given Amount = 23400, R = 10% and T = 3 years
A = 21780
The amount of the same sum in 2 years and at 10% p.a. compound interest is 21780.
10. Mohit borrowed a certain sum at 5% per annum compound interest and cleared this loan by paying Rs. 12,600 at the end of the first year and Rs. 17,640 at the end of the second year. Find the sum borrowed.
Answer
For the payment of Rs. 12,600 at the end of first year :
A = Rs. 12,600; n = 1 year and r = 5%
∴ Sum borrowed = Rs. (12,000 + 16,000 ) = Rs. 28,000.
Exercise 3(C)
1. If the interest is compounded half-yearly, calculate the amount when principal is Rs. 7,400; the rate of interest is 5% per annum and the duration is one year.
Answer
Given: P = Rs. 7,400; r = 5% p.a. and n = 1 year
Since the interest is compounded half-yearly,
= Rs. 7,774.63
Answer
(i) When interest is compounded yearly :
Given : P = Rs. 10,000 ; n = 18 months = 1.5 year and r = 10% p.a.
For 1 year
C.I.= Rs.11,576.25 – Rs.10,000 = Rs. 1,576.25
Difference between both C.I. = Rs. 1,576.25 – Rs. 1,550 = Rs. 26.25
20% simple interest for the first 2 years.
20% C.I. for the remaining one year on the amount due after 2 years, the interest being compounded half-yearly.
Find the total amount to be paid at the end of the three years.
Answer
For the first 2 years
⇒ A = 27,104
The total amount to be paid at the end of the three years is Rs. 27,104.
Answer
⇒ P = 24,000
The sum of Rs. 24,000 amount Rs. 27,783 in one and a half years at 10% per annum compounded half yearly.
Answer
(i) For Ashok (interest is compounded yearly) :
Let P = Rs. y; n = 18 months = 1.5 year and r = 20% p.a.
For 1 year
Money invested by each person=Rs. 3,000.
Answer
⇒ r = 8
The rate of interest is 8%.
Answer
Given: P=Rs. 1,500; C.I.= Rs. 496.50 and r = 20%
Since interest is compounded semi-annually
8. Calculate the C.I. on Rs. 3,500 at 6% per annum for 3 years, the interest being compounded half-yearly.
Do not use mathematical tables. Use the necessary information from the following:
(1.06)3 =1.191016; (1.03)3 = 1.092727
(1.06)6 =1.418519; (1.03)6 = 1.194052
Answer
Given : P = Rs. 3,500; r = 6% and n = 3 years
Since interest is being compounded half-yearly
= 3,500[(1.03)6 – 1]
= 3,500[1.194052 – 1]
= 3,500 × 0.194052
= Rs. 679.18
Answer
= Rs. 13,860
∴ C.I. = Rs. 13,860 – Rs. 12,000 = Rs. 1,860
∴Difference between C.I. and S.I.
= Rs. 1,860 – Rs. 1,800 = Rs. 60.
Answer
A = Rs. 13,891.50
C.I. = Rs. 13,891.50 – Rs. 12,000 = Rs. 1,891.50
∴ Difference between C.I. and S.I = Rs. 1,891.50 – Rs. 1,800 = Rs. 91.50.
Exercise 3(D)
1.The cost of a machine is supposed to depreciate each year at 12% of its value at the beginning of the year. If the machine is valued at Rs. 44,000 at the beginning of 2008, find its value :
(i) at the end of 2009.
(ii) at the beginning of 2007.
Answer
Cost of machine in 2008 = Rs. 44,000
Depreciation rate = 12%
(i) ∴ Cost of machine at the end of 2009
2. The value of an article decreases for two years at the rate of 10% per year and then in the third year it increases by 10%. Find the original value of the article, if its value at the end of 3 years is Rs. 40,095.
Answer
Let X be the value of the article.
The value of an article decreases for two years at the rate of 10% per year.
The value of the article at the end of the 1st year is
X – 10% of X = 0.90X
The value of the article at the end of the 2nd year is
0.90X – 10% of (0.90X) = 0.81X
The value of the article increases in the 3rd year by 10%.
The value of the article at the end of 3rd year is
0.81x + 10% of (0.81x) = 0.891x
The value of the article at the end of 3 years is Rs. 40,095.
0.891X = 40,095
⇒ X = 45,000
The original value of the article is Rs. 45,000.
Answer
Population in 2009 (P) = 64,000
Let after n years its population be 74,088(A)
Growth rate= 5% per annum
On comparing, we get,
n = 3 years
Answer
Let the population in the beginning of 1998 = P
The population at the end of 1999 = 2,85,120(A)
r1 = – 12% and r2 = + 8%
5. A sum of money, invested at compound interest, amounts to Rs. 16,500 in 1 year and to Rs. 19,965 in 3 years. Find the rate per cent and the original sum of money invested.
Answer
Let sum of money be Rs P and rate of interest = r %
Money after 1 year = Rs. 16,500
Money after 3 years = Rs. 19,965
For 1 year
6. The difference between C.I. and S.I. on Rs. 7,500 for two years is Rs. 12 at the same rate of interest per annum. Find the rate of interest.
Answer
Given : P = Rs. 7,500 and Time(n) = 2 years
Let rate of interest = y%
⇒ y2 = 16
⇒ y = 4 %
Answer
Let Principal be Rs y and rate= r%
According to 1st condition
Amount in 10 years = Rs 3
On comparing, we get
n = 10×3 = 30 years
Answer
At the end of the two years the amount is
⇒ P = Rs. 40,000
Mr. Sharma borrowed Rs. 40,000.
Answer
Let sum of money be Rs. y
To calculate S.I.
⇒ y/400 = 15 ⇒ y = Rs. 6,000.
Answer
Let Rs.X and Rs.Y be the money invested by Pramod and Rohit respectively such that they will get the same sum on attaining the age of 25 years.
Pramod will attain the age of 25 years after 25 – 16 = 9 years
Rohit will attain the age of 25 years after 25 -18 = 7 years
Pramod and Rohit should invest in 400 : 441 ratio respectively such that they will get the same sum on attaining the age of 25 years.
Exercise 3(E)
Answer
1st case
Given: S.I. = Rs 450 ; Time = 2 years and Rate = 4%
= Rs. 5852.25
∴ C.I. = 5,852.25 – 5,625 = Rs. 227.25
Answer
Given : P = Rs. 10,800 ; Time = 2.5 years and Rate = 10% p.a.
For 2 years
∴ Rs.13,721 – Rs.10,800 = Rs.2,921
- Its value after 2 years.
- Its value when it was purchased.
Answer
(i) Present value of machine(P) = Rs.97,200
Depreciation rate = 10%
Answer
Let the sum of money lent by both Rs. y
For Anuj
P = Rs. y ; rate = 8% and time = 2 years
5.Calculate the sum of money on which the compound interest (payable annually) for 2 years be four times the simple interest on Rs. 4,715 for 5 years, both at the rate of 5% per annum.
Answer
Given : Principal = Rs.4,715; time = 5 years and rate= 5% p.a.
Answer
Given : C.I. for the 2nd year = Rs. 4,950 and rate = 15%
The sum invested is Rs.30,000.
Answer
Let the sum of money be Rs. y
and rate = 10% p.a. compounded half yearly
y = 3600.
Answer
P = Rs. 86,000; time = 2 years and rate = 5% p.a.
To calculate S.I
Profit = C.I. - S.I. = Rs.8,815 - Rs.8,600 = Rs.215
Answer
Let Rs.X be the sum of money.
Rate = 5 % p.a. Simple interest = Rs.1,200, n = 3 years.
⇒ A = 8,000( 1.1025 )
⇒ A = 8,820
C.I. = A – P
⇒ C.I. = 8,820 – 8,000
⇒ C.I. = 820.
The amount due after 2 years is Rs. 8,820 and the compound interest is Rs. 820.
(a) The rate of interest.
(b) The amount at the end of the second year.
Answer
Let X % be the rate of interest.
P = Rs. 6,000, n = 2 years, A = Rs.6,720
For the first year
⇒ A = 7,526.40
The amount at the end of the second year = Rs. 7,526.40