ICSE Solutions for Selina Concise Chapter 1 GST [Goods and Service Tax] Class 10 Maths
Exercise 1(A)
1. For the following transaction within Delhi, fill in the blanks to find the amount of bill:
MRP = Rs 12,000, Discount % = 30%, GST = 18%
Discount =
Selling price (discounted value) =
CGST =
SGST =
IGST =
Amount of Bill =
Solution
Given,
MRP = Rs 12,000, Discount % = 30%, GST = 18%
Now,
Discount = 30% of 12,000 = (30/100) × 1200 = Rs 3600
So,
Selling price (discounted value) = 12000 – 3600 = Rs 8400
CGST = 9% of 8400 = Rs 756
SGST = 9% of 8400 = Rs 756
IGST = 0
Thus, the amount of bill = Selling price + CGST + SGST
= 8400 + 756 + 756
= Rs 9912
2. For the following transaction from Delhi to Jaipur, fill in the blanks to find the amount of bill:
MRP = Rs 50,000, Discount % = 20%, GST = 28%
Discount =
Selling price (discounted value) =
CGST =
SGST =
IGST =
Amount of Bill =
Solution
Given,
MRP = Rs 50,000, Discount % = 20%, GST = 28%
Now,
Discount = 20% of 50,000 = (20/100) ×50,000 = Rs 10,000
So,
Selling price (discounted value) = 50,000 – 10,000 = Rs 40,000
CGST = 0
SGST = 0
IGST = 28% of 40,000 = (28/100) ×40,000 = Rs 11,200
Thus, the amount of bill = Selling price + IGST
= 40,000 + 11,200
= Rs 51,200
3. A computer mechanic in Delhi charges repairing cost from five different persons A, B, C, D and E with certain discounts. The repairing costs and the corresponding discounts are as given below:
| Name of the person | A | B | C | D | E |
| Repairing cost (in Rs) | 5500 | 6250 | 4800 | 7200 | 3500 |
| Discount % | 30 | 40 | 30 | 20 | 40 |
If the rate of GST is 18%, find the total money (including GST) received by the mechanic.
Solution
| Name of the person | Repairing cost (in Rs) | Discount % | Discount | Selling price | CGST (9%) | SGST (9%) |
| A | 5500 | 30 | 1650 | 3850 | 346.5 | 346.5 |
| B | 6250 | 40 | 2500 | 3750 | 337.5 | 337.5 |
| C | 4800 | 30 | 1440 | 3360 | 302.4 | 302.4 |
| D | 7200 | 20 | 1440 | 5760 | 518.4 | 518.4 |
| E | 3500 | 40 | 1400 | 2100 | 189 | 189 |
| Total | 18,820 | 1693.8 | 1693.8 |
Thus,
The total money (including GST) received by the mechanic is 18,820 + 1693.8 + 1693.8 = Rs. 22,207.60
4. Find the amount of bill for the following intra-state transaction of goods/services. The GST rate is 5%.
| Quantity (no. of items) | MRP of each item (in Rs.) | Discount % |
| 18 | 150 | 10 |
| 24 | 240 | 20 |
| 30 | 100 | 30 |
| 12 | 120 | 20 |
Solution
| Quantity | MRP | Total MRP | Discount % | Discounted price | Selling price | CGST 2.5% | SGST 2.5% |
| 18 | 150 | 2700 | 10 | 270 | 2430 | 60.75 | 60.75 |
| 24 | 240 | 5760 | 20 | 1152 | 4608 | 115.2 | 115.2 |
| 30 | 100 | 3000 | 30 | 900 | 2100 | 52.5 | 52.5 |
| 12 | 120 | 1440 | 20 | 288 | 1152 | 28.8 | 28.8 |
| Total | 10,290 | 257.25 | 257.25 |
Thus,
The amount of bill = Selling price + GST
= 10,290 + 257.25 + 257.25
= Rs. 10,804.5
5. Find the amount of bill for the following inter-state transaction of goods/services. The GST rate is 18%.
| Quantity (no. of items) | 35 | 47 | 20 |
| MRP of each item (in Rs.) | 420 | 600 | 350 |
| Discount % | 10 | 10 | 20 |
Solution
| Quantity | MRP | Total MRP | Discount % | Discounted price | Selling price | CGST 9% | SGST 9% |
| 35 | 420 | 14,700 | 10 | 1470 | 13,230 | 1190.7 | 1190.7 |
| 47 | 600 | 28,200 | 10 | 2820 | 25,380 | 2284.2 | 2284.2 |
| 20 | 350 | 7000 | 20 | 1400 | 5600 | 504 | 504 |
| Total | 44,210 | 3978.9 | 3978.9 |
Thus,
The amount of bill = Selling price + CGST + SGST
= 44,210 + 3978.9 + 3978.9
= Rs. 52,167.80
6. Find the amount of bill for the following intra-state transaction of goods/services.
| MRP (in Rs.) | 12,000 | 15,000 | 9500 | 18,000 |
| Discount % | 30 | 20 | 30 | 40 |
| CGST % | 6 | 9 | 14 | 2.5 |
Solution
| MRP (in Rs.) | Discount
% |
CGST % | Discounted value | Selling price | CGST | SGST |
| 12,000 | 30 | 6 | 3600 | 8400 | 504 | 504 |
| 15,000 | 20 | 9 | 3000 | 12,000 | 1080 | 1080 |
| 9500 | 30 | 14 | 2850 | 6650 | 931 | 931 |
| 18,000 | 40 | 2.5 | 7200 | 10,800 | 270 | 270 |
| 37,850 | 2785 | 2785 |
Thus, the amount of bill = Selling price + CGST + SGST
= 37,850 + 2785 + 2785 = Rs. 43,420
7. For the data given above in questions no. 6, find the amount of bill for the inter-state transaction.
| MRP (in Rs.) | 12,000 | 15,000 | 9500 | 18,000 |
| Discount % | 30 | 20 | 30 | 40 |
| CGST % | 6 | 9 | 14 | 2.5 |
Solution
| MRP (in Rs.) | Discount | Discounted value | Selling price | IGST | IGST |
| 12,000 | 30 | 3600 | 8400 | 12 | 1008 |
| 15,000 | 20 | 3000 | 12,000 | 18 | 2160 |
| 9500 | 30 | 2850 | 6650 | 28 | 1862 |
| 18,000 | 40 | 7200 | 10,800 | 5 | 540 |
| 37,850 | 5570 |
Thus, the amount of bill = Selling price + GST
= 37,850 + 5570
= Rs. 43,420
8. A dealer in Mumbai supplied some items at the following prices to a dealer in Delhi. Find the total amount of the bill.
| Rate per piece (in Rs.) | Quantity (no. of pieces) | Discount % | SGST % |
| 180 | 10 | – | 9 |
| 260 | 20 | 20 | 9 |
| 310 | 30 | – | 9 |
| 175 | 20 | 30 | 9 |
Solution
| Rate per piece (in Rs.) | Quantity (no. of pieces) | Discount % | MRP | Selling price | IGST 18% |
| 180 | 10 | Net | 1800 | 1800 | 324 |
| 260 | 20 | 20 | 5200 | 4160 | 748.8 |
| 310 | 30 | Net | 9300 | 9300 | 1674 |
| 175 | 20 | 30 | 3500 | 2450 | 441 |
| 17,710 | 3187.8 |
Thus, the amount of bill = Selling price + IGST
= 17,710 + 3187.8
= Rs. 20,897.80
9. National Trading Company, Meerut (UP) made the supply of the following goods/services to Samarth Traders, Noida (UP). Find the total amount of bill if the rate of GST = 12%
| Quantity (no. of pieces) | 20 | 30 | 12 | 40 |
| MRP (in Rs. per piece) | 225 | 320 | 300 | 250 |
| Discount % | 40 | 30 | 50 | 40 |
Solution
| MRP (in Rs. per piece) | Quantity (no. of pieces) | Discount % | MRP | Selling price | SGST 6% | CGST 6% |
| 225 | 20 | 40 | 4500 | 2700 | 162 | 162 |
| 320 | 30 | 30 | 9600 | 6720 | 403.2 | 403.2 |
| 300 | 12 | 50 | 3600 | 1800 | 108 | 108 |
| 250 | 40 | 40 | 10,000 | 6000 | 360 | 360 |
| 17,220 | 1033.2 | 1033.2 |
Thus, the amount of bill = Selling price + SGST + CGST
= 17,220 + 2066.4
= Rs. 19,286.4
10. M/s Ram Traders, Delhi, provided the following services to M/s Geeta Trading Company in Agra (UP). Find the amount of bill:
| Number of services | 8 | 12 | 10 | 16 |
| Cost of each service (in Rs.) | 680 | 320 | 260 | 420 |
| GST % | 5 | 12 | 18 | 12 |
Solution
| Number of services | Cost of each service (in Rs.) | GST % | MRP | IGST |
| 8 | 680 | 5 | 5440 | 272 |
| 12 | 320 | 12 | 3840 | 460.8 |
| 10 | 260 | 18 | 2600 | 468 |
| 16 | 420 | 12 | 6720 | 806.4 |
| 18,600 | 2007.2 |
Thus, the amount of bill = Selling price + IGST
= 18,600 + 2007.2
= Rs. 20,607.2
11. For the following, find the amount of bill data:
| Rate per piece (in Rs.) | Number of pieces | Discount % | GST% |
| 18 | 360 | 10 | 12 |
| 12 | 480 | 20 | 18 |
| 12 | 120 | 5 | 12 |
| 28 | 150 | 20 | 28 |
Solution
| Rate per piece (in Rs.) | Number of pieces | Discount % | MRP (in Rs.) | Selling price (in Rs.) | GST % | GST (in Rs.) |
| 18 | 360 | 10 | 6480 | 5832 | 12 | 699.84 |
| 12 | 480 | 20 | 5760 | 4608 | 18 | 829.44 |
| 12 | 120 | 5 | 1440 | 1368 | 12 | 164.16 |
| 28 | 150 | 20 | 4200 | 3360 | 28 | 940.8 |
| 15,168 | 2634.24 |
Thus, the amount of bill = Selling price + GST
= 15,168 + 2634.24
= Rs. 17,802.24
12. The tax invoice of a telecom service in Meerut shows cost of services provided by it as Rs. 750. If the GST rate is 18%, find the amount of the bill.
Solution
From the question, we have
GST = 18% of 750
= 18/100 × 750 = Rs. 135
Thus, the amount of bill = 750 + 135 = Rs. 885
13. Mr. Pankaj took Health Insurance Policy for his family and paid Rs. 900 as SGST. Find the total annual premium paid by him for this policy, rate of GST being 18%.
Solution
Let’s consider that the total annual premium paid by Mr. Pankaj be Rs. X.
Then, from the question
18% of X = SGST + CGST
18% of X = 1800 [as SGST = CGST]
So, 18/100 × X = 1800
X = Rs. 10,000
∴ the total annual premium paid by him for the policy is Rs. 10,000
14. Mr. Malik went on a tour to Goa. He took a room in a hotel for two days at the rate of Rs. 5000 per day. On the same day, his friend John also joined him. Hotel provided an extra bed charging Rs. 1000 per day for the bed. How much GST, at the rate of 28% is charged by the hotel in the bill to Mr. Malik for both the days?
Solution
From the question, we have
The amount of bill = cost of hotel room x no. of days + additional bed charges for the 2 days
= 5000 × 2 + 1000 + 1000
= 10,000 + 2000
= Rs. 12,000
And,
GST = 28% of 12,000
= 28/100 × 12,000 = 3360
∴ the GST charged by the hotel in the bill to Mr. Malik is Rs. 3360.
15. Asharaf went to see a movie. He wanted to purchase a movie ticket for Rs. 80. As the ticket for Rs. 80 was not available, he purchased a ticket for Rs. 120 of upper class. How much extra GST did he pay for the ticket? (GST for a ticket below Rs. 100 is 18% and GST for a ticket above Rs. 100 is 28%)
Solution
From the question, we have
GST on ticket of Rs. 80 = 18% of 80 = 18/100 × 80 = Rs. 14.40
GST on ticket of Rs. 120 = 28% of 120 = 28/100 × 120 = Rs. 33.60
So,
The difference between both GST = 33.60 – 14.40 = Rs. 19.20
Thus, the extra GST Asharaf paid for the ticket is Rs. 19.20
Exercise 1(B)
1. Fill in the blanks:
When the goods/services are sold for Rs. 15,000 under intra-state transaction from station A to station B and the rate of GST is 12%.
As per GST System
(a) S.P. at station A = ……
(b) CGST = 6% of 15,000 = ……
SGST = 6% of 15,000 = ……
(c) C.P. at station B = ……
(d) If profit = Rs. 5000
S.P. at station B = ……
Now the same goods/services are moved under inter-state transaction from station B to station C and the rate of tax is 12%.
(e) GST = ……
(f) C.P. at station C = ……
Solution
When the goods/services are sold for Rs. 15,000 under intra-state transaction from station A to station B and the rate of GST is 12%.
As per GST System
(a) S.P. at station A = Rs. 15,000
(b) CGST = 6% of 15,000 = Rs. 900
SGST = 6% of 15,000 = Rs. 900
(c) C.P. at station B = Rs. 15,000
(d) If profit = Rs. 5000
S.P. at station B = 15,000 + 5000 = Rs. 20,000
Now the same goods/services are moved under inter-state transaction from station B to station C and the rate of tax is 12%.
(e) GST = 12% of 20,000 = Rs. 2400
(f) C.P. at station C = Rs. 20,000
2. Goods/services are sold from Agra (U.P.) to Kanpur (U.P.) for Rs. 20,000 and then from Kanpur to Jaipur (Rajasthan). If the rate of GST is 18% and the profit made at Kanpur is Rs. 5000, find:
(i) the net GST payable by the dealer at Kanpur.
(ii) the cost of goods/services at Jaipur.
Solution
From the question, when the product is sold from Agra to Kanpur (intra-state transaction)
For the dealer in Agra:
S. P. in Agra = Rs. 20,000
CGST = 9% of Rs. 20,000 = 9/100 × 20,000 = 1800
SGST = 9% of Rs. 20,000 = 9/100 × 20,000 = 1800
Now, when the product is sold from Kanpur to Jaipur (inter-state transaction)
For the dealer in Kanpur
Input-tax credit = 1800 + 1800 = Rs. 3600
C. P. = Rs. 20,000 and Profit = Rs. 5000
So, the S.P. = 20,000 + 5000 = Rs. 25,000
IGST = 18% of 25,000 = Rs. 4500
(i) Net GST paid by the dealer at Kanpur
= Output GST – Input GST
= 4500 – 3600 = Rs. 900
(ii) The cost of goods/services at Jaipur
= S. P. in Agra + IGST
= 25,000 + 18% of 25000
= 25,000 + 4500 = Rs. 29,500
3. Goods/services are sold from Kota (Rajasthan) to Mumbai for Rs. 20,000 and then from Mumbai to Pune. If the rate of GST is 12% and the profit made at Mumbai is Rs. 5000; find the net GST paid at Pune, if the dealer at Pune is the end-user.
Solution
From the question, we have
For the dealer in Mumbai (inter-state transaction)
CP = Rs. 20,000
IGST = 12% of Rs. 20,000 = 12/100 × 20,000 = Rs. 2400
Given, Profit = Rs. 5000
SP = Rs. 25,000
Now, for the dealer in Pune (intra-state transaction)
CP = Rs. 25,000
CGST = 6% of 25,000 = Rs. 1500
SGST = 6% of 25,000 = Rs. 1500
Thus, the GST paid by the end user at Pune is Rs (1500 + 1500) = Rs. 3000
4. A is a dealer in Banaras (U.P.). he supplies goods/services worth Rs. 8000 to a dealer B in Agra (U.P.). Dealer B, in turn, supplies the same goods/services to dealer C in Patna (Bihar) at a profit of Rs. 1200. Find the input and output taxes for the dealer C under GST system; if the rate of GST is 18% and C does not sell his goods/services further.
Solution
From the question,
For the dealer A (intra-state transaction)
SP = Rs. 8,000
For the dealer B (intra-state transaction)
CP = Rs. 8,000
CGST = 9% of 8,000 = Rs. 720
SGST = 9% of 8,000 = Rs. 720
Given profit = Rs. 1,200
SP = Rs. 9,200
For the dealer C (inter-state transaction)
CP = Rs. 9,200
IGST = 18 % of Rs. 9,200 = 18/100 × 9200 = Rs 1656
Input Tax = Rs. 1,656
As the dealer in Patna does not sell the product.
Thus, the output GST (tax on sale) = Rs. 0
5. A is a dealer in Meerut (U.P.). He supplies goods/services, worth Rs. 15,000 to a dealer B in Ratlam (M.P.). Dealer B, in turn, supplies the same goods/services to dealer C in Jabalpur (M.P.) at a profit of Rs. 3000. If rate of tax (under GST system) is 18%, find :
(i) The cost of goods/services to the dealer C in Jabalpur.
(ii) Net tax payable by dealer B.
Solution
From the question,
For A (case of inter-state transaction)
S.P. in Meerut = Rs. 15,000
For B (case of inter-state transaction)
C.P. = Rs. 15,000
IGST = 18% of 15,000 = 18/100 × 15,000 = Rs. 2700
Now, the input tax for B = Rs. 2,700
And the S.P. in Ratlam = 15,000 + 3000 = Rs. 18,000
For C (case of intra-state transaction)
C.P. = Rs. 18,000
CGST = 9% of 18,000 = 9/100 x 18,000 = Rs. 1620
SGST = 9/100 × 18,000 = Rs. 1620
(i) Cost for the dealer C in Jabalpur
= S.P. for the dealer in Ratlam + GST
= 18,000 + 1620 + 1620 = Rs. 21,240
(ii) Output tax for B = Rs. 1620 + Rs. 1620 = Rs. 3240
Net GST payable by the dealer B
= Output tax – Input tax
= 1620 + 1620 – 2700 = Rs. 540
6. A dealer X in Hapur (U.P.) supplies goods/services, worth Rs. 50,000 to some other dealer Y in the same city. Now the dealer Y supplies the same goods/services to dealer Z in Calcutta at a profit of Rs. 20,000. Find:
(i) Output and input taxes for the dealer Y
(ii) Net GST payable by dealer Y.
[The rate of GST at each stage is 28%]
Solution
From the question, we have
For the dealer X (intra-state transaction)
The SP = Rs. 50,000
For the dealer Y (intra-state transaction)
CP = Rs. 50,000
CGST = 14% of 50,000 = Rs. 7,000
SGST = 14% of 50,000 = Rs. 7,000
So, the input tax for dealer Y = Rs. 14,000
Profit = Rs. 20,000
SP = Rs. 70,000
For the dealer Z (inter-state transaction)
CP = Rs. 70,000
IGST = 28 % of Rs. 70,000 = 28/100 × 70,000 = Rs. 19,600
Thus, the input tax = Rs. 19,600 which becomes the output tax for dealer Y.
Now,
The net GST payable for Y will be
= Output tax for Y – Input tax for Y
= 19,600 – 14,000
= Rs. 5600
7. Consultancy services, worth Rs. 50,000, are transferred from Delhi to Calcutta at the rate of GST 18% and then from Calcutta to Nainital (with profit = Rs. 20,000) at the same rate of GST. Find the output tax at
(i) Delhi
(ii) Calcutta
(iii) Nainital
Solution
(i) Output tax in Delhi (inter-state):
IGST = 9% of 50,000 = Rs. 4500
Thus, the output tax in Delhi = Rs. 4500
(ii) Output tax in Calcutta:
C.P. in Calcutta = Rs. 50,000 and Profit = Rs. 20,000
S.P. in Calcutta = 50,000 + 20,000 = Rs. 70,000
IGST = 18% of 70,000 = Rs. 12,600
Thus, the output tax in Calcutta = Rs. 12,600
(iii) Since, the dealer in Nainital does not sell the product.
Thus, the output GST (tax on sale) = Rs. 0
8. For a dealer A, the list price of an article is Rs. 9000, which he sells to dealer B at some lower price. Further, dealer B sells the same article to a customer at its list price. If the rate of GST is 18% and dealer B paid a tax, under GST, equal to Rs. 324 to the government, find the amount (inclusive of GST) paid by dealer B.
Solution
Let dealer A sell to dealer B at Rs. x lower price.
Then from the question,
Net Tax paid by dealer B is
⇒ Output tax – Input Tax = Rs. 324
⇒ 18% of 9000 – 18% of (9000 – x) = 324
⇒ 1620 – 1620 + 18% of x = 324
⇒ 18% of x = 324
⇒ x = 1800
∴ the selling price of B = 9000 – 1800 = Rs. 7200
And, The amount (inclusive of GST) paid by dealer B
= 7200 + 18% of 7200
= 7200 + 1296
= Rs. 8496
9. The marked price of an article is Rs. 6000. A wholesaler sells it to a dealer at 20% discount. The dealer further sells the article to a customer at a discount of 10% on the marked price. If the rate of GST at each stage is 18%, find the amount of tax (under GST) paid by the dealer to the government.
Solution
We have,
Initial marked price by manufacturer A is Rs. 6000
Then, B bought the T.V. at a discount of 20%.
Now, Cost price of B = 80% of 6000 = Rs. 4800
And, GST paid by B for purchase = 18% of 4800 = Rs. 864
Again, B sells T.V. at discount of 10% of market Price
So, the Selling price for B = 6000 – 10% of 6000 = Rs. 5400
And, GST charged by B on selling of T.V. = 18% of 5400 = Rs. 972
Thus, GST paid by B to the government
= GST charged on selling price – GST paid against purchase price
= 972 – 864 = Rs. 108
10. A is a manufacturer of T.V. sets in Delhi. He manufacturers a particular brand of T.V. set and marks it at Rs. 75,000. He then sells this T.V. set to a wholesaler B in Punjab at a discount of 30%. The wholesaler B raises the marked price of the T.V. set bought by 30% and then sells it to dealer C in Delhi. If the rate of GST = 5% find tax (under GST) paid by wholesaler B to the government.
Solution
We know that,
Initial marked price by manufacturer A is Rs. 75,000
Then, B bought the T.V. at a discount of 30%.
So, the Cost price of B = 70% of 75,000 = Rs. 52,500
And, GST paid by B for purchase = 5% of 52,500 = Rs. 2625
Now, B sells T.V. by increasing marked price by 30%.
Then, the Selling price for B = 75,000 + 30% of 75,000 = Rs. 97,500
And, GST charged by B on selling of T.V. = 5% of 97,500 = Rs. 4875
Thus, the GST paid by B to the government
= GST charged on selling price – GST paid against purchase price
= 4875 – 2625
= Rs. 2250
11. For a trader, marked price of a refrigerator = Rs. 15,680 inclusive of GST at the rate of 12% on the marked price. Gagan, a customer for this refrigerator, asks the trader to reduce the marked price of the refrigerator to such extend that its reduced price plus GST on it is equal to marked price of the refrigerator. Find the required reduction.
Solution
Let us assume the marked price of the refrigerator be Rs. x.
Which is inclusive of GST (12%)
So,
x + 12% of x = 15,680
1.12x = 15,680
x = Rs. 14,000
Initial marked price = Rs. 14,000
Now,
Let Rs. y be the price reduction asked by Gagan.
So, the new price = 14,000 – y
And, GST on new price = 12% of (14,000 – y)
From the question,
14,000 – y + 0.12(14,000 – y) = 14,000
-1.12y + 1680 = 0
y = 1500
∴ the required reduction in price is Rs. 1500.